Timeline
Timeline
2025-09-13
init
Counting sort
Problem:
Use counting sort idea, trade space for time, complexity O(n)
1234567891011121314151617181920212223242526272829303132333435363738394041424344 | bool isVowel(char c){ if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' || c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') { return true; } return false;}int maxFreqSum(char *s){ int len; int arr[58]; len = strlen(s); memset(arr, 0, 58 * sizeof(int)); for (int i = 0; i < len; i++) { arr[s[i] - 'A']++; } int vowel_max = 0; int consonant_max = 0; for (int i = 0; i < 58; i++) { if (isVowel('A' + i) && arr[i] > vowel_max) { vowel_max = arr[i]; } if (!isVowel('A' + i) && arr[i] > consonant_max) { consonant_max = arr[i]; } } return vowel_max + consonant_max;}int main(){ int n; n = maxFreqSum("successes"); printf("%d", n);} |
