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2026-03-20
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Dynamic Programming
Problem:
Dynamic Programming
12345678910111213141516171819202122232425262728293031323334 | using std::vector;class Solution { public: int numSquares(int n) // 12 { int i, j; vector<int> perfect_squares; vector<int> dp(n + 1, n + 1); for (i = 1; i * i <= n; i++) perfect_squares.push_back(i * i); // 1 4 9 dp[0] = 0; for (i = 1; i <= n; i++) { for (j = 0; j < perfect_squares.size() && perfect_squares[j] <= i; j++) dp[i] = std::min(dp[i], dp[i - perfect_squares[j]] + 1); } return dp[n]; }};int main(){ Solution S; int num = S.numSquares(12); printf("%d\n", num); num = S.numSquares(13); printf("%d\n", num);} |
