while first != n - 1 { if bank[first].contains('1') { break; } else { first += 1; } } if first == n { return0; } last_num = bank[first].chars().filter(|&ch| ch == '1').count();
foriin first + 1..n { curr_num = bank[i].chars().filter(|&ch| ch == '1').count(); if curr_num > 0 { res += last_num * curr_num; last_num = curr_num; } }