时间轴

2025-12-02

init


题目:

把二维矩阵看成一维就行

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#include <vector>
using std::vector;

class Solution {
public:
bool searchMatrix(vector<vector<int> > &matrix, int target)
{
int m = matrix.size(), n = matrix[0].size();
int left = 0, right = m * n - 1;
int mid;
int mid_i, mid_j;

while (left <= right) {
mid = (left + right) / 2;
mid_i = mid / n;
mid_j = mid % n;
if (matrix[mid_i][mid_j] == target) {
return true;
} else if (matrix[mid_i][mid_j] < target) {
left = mid + 1;
} else {
right = mid - 1;
}
}
return false;
}
};

leetcode hot100 rewrite

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#include <vector>
using std::vector;

class Solution {
public:
bool binary_search(vector<int> nums, int target)
{
int n = nums.size();
int left = 0, right = n - 1, mid;

while (left <= right) {
mid = left + (right - left) / 2;

if (nums[mid] < target)
left = mid + 1;
else if (nums[mid] > target)
right = mid - 1;
else
return true;
}

return false;
}

public:
bool searchMatrix(vector<vector<int> > &matrix, int target)
{
int i, m = matrix.size();
for (i = 0; i < m; i++) {
if (target >= matrix[i].front() && target <= matrix[i].back())
return binary_search(matrix[i], target);
}

return false;
}
};