题目:
可以把链表分成两组,后面那组的尾部挂到前面那组即可
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| struct ListNode { int val; ListNode *next; ListNode() : val(0) , next(nullptr) { } ListNode(int x) : val(x) , next(nullptr) { } ListNode(int x, ListNode *next) : val(x) , next(next) { } };
class Solution { public: ListNode *rotateRight(ListNode *head, int k) { int nr_node = 0; ListNode *p = head, *new_head_prev, *new_head, *tail;
while (p != nullptr) { if (p->next == nullptr) { tail = p; } p = p->next; nr_node++; } if (nr_node == 0) { return head; } k = k % nr_node; if (k == 0) { return head; } new_head_prev = head; for (int i = 0; i < nr_node - k - 1; i++) { new_head_prev = new_head_prev->next; } new_head = new_head_prev->next; tail->next = head; new_head_prev->next = nullptr; return new_head; } };
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