leetcode每日一题 P3484 设计电子表格

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时间轴

时间轴

2025-09-19

init

模拟 C++字符串分割 string转int 哈希表

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题目：

P3484 设计电子表格

https://leetcode.cn/problems/design-spreadsheet/description/?envType=daily-question&envId=2025-09-19

这题直接模拟是可以过的，用哈希表会更好，因为行列是唯一的可以作为键值，这样就免去很多字符串转 int

#include <sstream>
#include <stdlib.h>
#include <string>
#include <utility>
#include <vector>

using std::pair;
using std::string;
using std::vector;

class Spreadsheet {
    private:
        vector<vector<int> > sheet;
        pair<int, int> get_row_and_column(const string &s)
        {
                int column = s[0] - 'A';
                int row;
                try {
                        row = std::stoi(s.substr(1).c_str());
                } catch (std::exception &e) {
                        printf("%s\n", e.what());
                        exit(-1);
                }
                row = row - 1;
                return { row, column };
        }

    public:
        Spreadsheet(int rows)
        {
                // 初始化
                sheet.assign(rows, vector<int>(26, 0));
        }

        void setCell(string cell, int value)
        {
                auto [row, column] = get_row_and_column(cell);
                sheet[row][column] = value;
        }

        void resetCell(string cell)
        {
                auto [row, column] = get_row_and_column(cell);
                sheet[row][column] = 0;
        }

        int getValue(string formula)
        {
                int res_value = 0;
                string formula_s = formula.substr(1);
                std::stringstream ss(formula_s);
                vector<string> values;
                string token;
                while (std::getline(ss, token, '+')) {
                        values.push_back(token);
                }
                int int_value;
                for (string value : values) {
                        try {
                                int_value = std::stoi(value);
                        } catch (std::invalid_argument) {
                                auto [row, column] = get_row_and_column(value);
                                int_value = sheet[row][column];
                        }
                        res_value += int_value;
                }
                return res_value;
        }
};

/**
 * Your Spreadsheet object will be instantiated and called as such:
 * Spreadsheet* obj = new Spreadsheet(rows);
 * obj->setCell(cell,value);
 * obj->resetCell(cell);
 * int param_3 = obj->getValue(formula);
 */
int main()
{
        // ["Spreadsheet","getValue"]
        // [[458],["=O126+10272"]]

        Spreadsheet *obj = new Spreadsheet(458);
        int result = obj->getValue("=O126+10272");
        printf("result is %d\n", result);
        delete obj;

        return 0;
}