时间轴

2025-12-04

init


题目:

二分本质是排除掉另一半:

  • 如果左半边是递增的且target不处于这个区间,那么target必定在右半边
  • 如果右半边是递增的且target不处于这个区间,那么target必定在左半边
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#include <vector>
using std::vector;

class Solution {
public:
int search(vector<int> &nums, int target)
{
int n = nums.size();
int left = 0, right = n - 1;
int mid;
while (left <= right) {
mid = left + (right - left) / 2;

if (nums[mid] == target) {
return mid;
}

if (nums[left] <= nums[mid]) {
if (nums[left] <= target &&
target < nums[mid]) {
right = mid - 1;
} else {
left = mid + 1;
}
}else if (nums[right] >= nums[mid]) {
if (nums[mid] < target &&
target <= nums[right]) {
left = mid + 1;
} else {
right = mid - 1;
}
}
}
return -1;
}
};