题目:
用哈希表来查找要删除的元素,将时间复杂度降低到 O(n)
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| #include <climits> struct ListNode { int val; ListNode *next; ListNode() : val(0) , next(nullptr) { } ListNode(int x) : val(x) , next(nullptr) { } ListNode(int x, ListNode *next) : val(x) , next(next) { } };
#include <vector> #include <unordered_set>
using std::vector; using std::unordered_set;
class Solution { public: ListNode *modifiedList(vector<int> &nums, ListNode *head) { int i, n; ListNode dummy; dummy.next = head; dummy.val = INT_MAX; ListNode *p = &dummy;
n = nums.size();
unordered_set<int> uset; ListNode *tmp;
for (i = 0; i < n; i++) { uset.insert(nums[i]); }
while (p->next) { if (uset.count(p->next->val) != 0) { tmp = p->next; p->next = tmp->next; delete tmp; }else{ p = p->next; } } return dummy.next; } };
#include <iostream> using std::cout; using std::endl;
int main() { vector<int> nums = {1, 2, 3}; ListNode *head = new ListNode(1, new ListNode(2, new ListNode(3, new ListNode(4, new ListNode(5)))));
Solution s; ListNode *res = s.modifiedList(nums, head);
while (res) { cout << res->val; if (res->next) cout << " -> "; res = res->next; } cout << endl;
return 0; }
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