时间轴

2025-11-19

init


题目:

可以先创建一个头节点方便进行尾插法,最后再释放。

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
struct ListNode {
int val;
ListNode *next;
ListNode()
: val(0)
, next(nullptr)
{
}
ListNode(int x)
: val(x)
, next(nullptr)
{
}
ListNode(int x, ListNode *next)
: val(x)
, next(next)
{
}
};

class Solution {
public:
ListNode *mergeTwoLists(ListNode *list1, ListNode *list2)
{
// 创建一个头节点
ListNode *list3_head = new ListNode;
ListNode *p = list3_head;

while (list1 != nullptr || list2 != nullptr) {
if (list1 == nullptr && list2 != nullptr) {
p->next = list2;
list2 = list2->next;
p = p->next;
p->next = nullptr;
} else if (list1 != nullptr && list2 == nullptr) {
p->next = list1;
list1 = list1->next;
p = p->next;
p->next = nullptr;
} else if (list1 != nullptr && list2 != nullptr) {
if (list1->val <= list2->val) {
p->next = list1;
list1 = list1->next;
p = p->next;
p->next = nullptr;
} else {
p->next = list2;
list2 = list2->next;
p = p->next;
p->next = nullptr;
}
}
}
p = list3_head;
list3_head = list3_head->next;
delete p;
return list3_head;
}
};